(2^4-3*5)q+13=(2*9-4^2)q+(3*4/12-1)

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Solution for (2^4-3*5)q+13=(2*9-4^2)q+(3*4/12-1) equation: 



(2^4-3*5)q+13=(2*9-4^2)q+(3*4/12-1)

We move all terms to the left:

(2^4-3*5)q+13-((2*9-4^2)q+(3*4/12-1))=0

We multiply parentheses

2q^5-15q-((2*9-4^2)q+(3*4/12-1))+13=0

We multiply all the terms by the denominator


2q^5*12-1))-15q*12-1))-((2*9-4^2)q+(3*4+13*12-1))=0

We do not support eqpression: q^5

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